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Calculate [OH^(-)] if pH = 5.284....

Calculate `[OH^(-)]` if pH = 5.284.

Text Solution

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`pH=-log_(10)[H^(+)],[H^(+)]="anti"log[-5.284]="anti"log[6-5.284-6]`
`[H^(+)]="anti"log(0.716-6)="anti"log[0.716]xx10^(-6)=5.2xx10^(-6)mol//dm^(3)`
`[H^(+)][OH^(-)]=10^(-14),SO[OH^(-)]=10^(-14)/([H^(+)])=10^(-14)/(5.2xx10^(-6))=0.192xx10^(-8)mol//dm^(3)`
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