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Calculate the [OH^(-)] of a solution who...

Calculate the `[OH^(-)]` of a solution whose pH is 9.62.

Text Solution

Verified by Experts

`pH+pOH=14" "pOH=14-pH=14-9.62=4.38`
`pOH=4.38=-log_(10)[OH^(-)],4.38=-log_(10)[OH^(-)]`
`log_(10)[OH^(-)]=-4.38` , Taking antilog on both the sides
`[OH^(-)]="anti"log(-4.38)="anti"log(5-4.38-5)`
= `"anti"log(0.62-5)="anti"log(0.62)xx10^(-5)=4.169xx10^(-5)"mol"dm^(-3)`.
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