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The pOH of a solution is 5.725. Calculat...

The pOH of a solution is 5.725. Calculate the `[H^(+)]`.

Text Solution

Verified by Experts

`pH+pOH=14" "pH=14-pOH=14-5.725=8.275`
`pH=-log_(10)[H^(+)]rArr8.275=log_(10)[H^(+)]rArr`
`[H^(+)]="anti"log(-8.275)="anti"log(9-8.275-9)`
`[H^(+)]="anti"log(0.275-9)=5.309xx10^(-9)"mol"dm^(-3)`
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