What is the pH of a buffer solution prepared by dissolving 0.1 mole of sodium acetate and 0.2 mole of acetic acid in enough water to make a `dm^(3)` of solution? (`K_(a)` of acetic acid = `1.8xx10^(-5)`).

Explanation

`pK_(a)=-logK_(a)`
= `-log1.8xx10^(-5)`
= -(5.2553)
= 4.7447
`pH=pK_(a)+"log"(["salt"])/(["acid"])`
= `4.74+"log"0.1/0.2`
= `474+log0.5`
= 4.74 - 0.3010
= 4.44