A buffer solution contains 2 moles of ammonium hydroxide and 0.25 mole of ammonium chloride per `dm^(3)` of the solution. (`K_(b)` for ammonium hydroxide = `1.8xx10^(-5)`). Calculate the pH of the buffer solution.

Explanation

It is a basic buffer
`pOH=pK_(b)+"log"(["Salt"])/(["Base"])`
= `4.74+"log"0.25/2=4.74+"log"0.25/2`
= 4.74 - 0.90 = 3.64
pH = 14 - 3.64
= 10.36