For the reaction `A+BhArrC+D`, the equilibrium constant is 0.05 at 300K. Calculate the equilibrium constant for `C+DhArrA+B` at the same temperature.

Explanation

Initial concentration `underset(0.8)(A)+underset(0.8)(B)hArrunderset(0)(C)+underset(0)(D)`
`{:("Molar concentration"),("at equilibrium"):}}{:(0.8-0.6,0.8-0.6),(=0.2,=0.2):}" "0.6" "0.6`
`therefore` [A] = 0.2 mol/L , [B] = 0.2 mol/L , [C] = 0.6 mol/L , [D] = 0.6 mol/L.
`thereforeK=([C][D])/([A][B])=(0.6xx0.6)/(0.2xx0.2)=9`