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For the reaction, 2NOCl(g)hArr2NO(g)+Cl(...

For the reaction, `2NOCl(g)hArr2NO(g)+Cl_(2)(g)` the value of `K_(c)=3.75xx10^(-6)` at 1069K. Calculate `K_(p)`.

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Since unit is not mentioned, it is to be assumed that the concentration is expressed in mol `L^(-)`. Hence, R = 0.0831 L bar `K^(-1)mol^(-1).Deltan` for the reaction is 3 - 2 = 1. `K_(p)=K_(c)(RT)^(Deltan)` becomes `K_(p)=K_(c)RT`
`K_(p)=(3.75xx10^(-6))0.0831xx1069=3.33xx10^(-4)`.
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