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PCl(3),Cl(2),PCl(5) are in equilibrium i...

`PCl_(3),Cl_(2),PCl_(5)` are in equilibrium in a closed vessel at 500K. The equilibrium concentration are 1.6 mol `L^(-1), 1.6"mol" L^(-1)and1.4"mol"L^(-1)` respectively. Calculate `K_(c)andK_(p)" for "PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)`.

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`K_(c)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=(1.6xx1.6)/1.4=1.828`
`Deltan=2-1=1`
`thereforeK_(p)=K_(c)(RT)^(Deltan)" becomes "=1.828(0.0831xx500)^(1)=75.95`.
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