A buffer solution of pH = 4.7 is prepared from `CH_(3)COONa and CH_(3)COOH`. Dissociation constant of acetic acid is `1.75xx10^(-5)`. Calculate the mole proportion of sodium acetate and acetic acid.

Explanation

`pH=pK_(a)+"log"(["Salt"])/(["Acid"])rArrpH=-log_(10)K_(a)+"log"([CH_(3)COONa])/([CH_(3)COOH])`
`4.7=-log_(10)(1.75xx10^(-5))+"log"([CH_(3)COONa])/([CH_(3)COOH])`
`4.7=5-log1.75+"log"([CH_(3)COONa])/([CH_(3)COOH])=5-0.2430+"log"([CH_(3)COONa])/([CH_(3)COOH])`
`"log"([CH_(3)COONa])/([CH_(3)COOH])="anti"log(-0.0557)="anti"log(-0.057+1-1)`
`([CH_(3)COONa])/([CH_(3)COOH])=0.8770`.