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Balance the following redox reaction by ...

Balance the following redox reaction by using Oxidation number method in acidic medium.`Cr_2O_7^-2(aq)+SO_3^_2(aq)rarrCr^+3(aq)+SO_4^-2(aq)`

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`Cr_(2)O_(7)^(2-)+SO_(3)^(2-)toCr^(3+)+SO_(4)^(2-)`(Acidic medium)

`Cr_(2)O_(7)^(2-)overset(cancel(2)xx3"units")(to)2Cr^(3+)` Reduction
`SO_(3)^(2-)overset(cancel(2)"units")(to)SO_(4)^(2-)` Oxidation
multiply reduction equation by 1 unit and oxidation equation by 3 units
`Cr_(2)O_(7)^(2-)to2Cr^(3+)`
`3SO_(3)^(2-)to3SO_(4)^(2-)`
Adding both equation `Cr_(2)O_(7)^(2-)+3SO_(3)^(2-)to2Cr^(3+)+3SO_(4)^(2-)`
Since there are 4 oxygen atom more on LHS, `4H_(2)O` is added on RHS. The equation is balanced WRT H+Ion.
`Cr_(2)O_(7)^(2-o)+3SO_(3)^(2-)+8H^(+)to2Cr^(3+)+3SO_(4)^(2-)+4H_(2)O`
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