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Calculate the pH of 0.01 MH2SO4 by assum...

Calculate the pH of 0.01 M`H_2SO_4` by assuming complete ionisation.

Text Solution

Verified by Experts

`pH=-log[H^(+)]" "underset(0.01M)(H_(2)SO_(4))tounderset(0.01xx2)(2H^(+))+SO_(4)^(-2)`
`pH=-log[2xx10^(-2)]" "[H^(+)]=0.02M`
`=1.4990`
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