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Expain the depression in freezing point ...

Expain the depression in freezing point of solution.

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* When a non-volatile solute is added to solvent vapour pressure of a solution decreases.
* This solution has lower freezing point than the freezing point of pure solvent.
* For a dilute solution depression of freezing point `(DeltaT_(f))` is directly proportion to molality (m) of the solution.
`DeltaT_(f)alpham" "DeltaT_(f)=K_(f)m`
`DeltaT_(f)` is depression in freezing point, i.e., `DeltaT_(f)=DeltaT_(f)^(0)-T_(f)`
`T_(f)` is freezing point of solution.
`T_(f)^(0)` is freezing point of solvent.
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An aqueous solution freezes at 272.4 K while pure water freezes at 273 K. Given K_(f)=1.86 K kg "mol"^(-1) , K_(b)=0.512 K kg "mol"^(-1) and vapour pressure of water at 298 K = 23.756 mm Hg. Determine the following. Depression in freezing point of solution

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If the elevation in boiling point of a solution of non-volatile, non-electrolytic and non-associating solute in a solvent ( K_(b)=x "K kg mol"^(-1) ) is y K, then the depression in freezing point of the same concentration would be ( K_(f) of the solvent = z "K kg mol"^(-1) )

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SUBHASH PUBLICATION-SOLUTIONS-PROBLEM SECTION
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  3. 5.8 g of non - volatile, non - electrolyte solute was dissolved in 100...

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