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If 1.71 g of sugar (molar mass=342) is d...

If 1.71 g of sugar (molar mass=342) is dissoved in 500 `cm^(3)` of a solution at 300K. What will be its osmotic pressure?

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Mass of solute=`W_(2)=1.71g" Molar mass of solute"=M_(2)=342`
Volume of solution=500`cm^(3)=0.5L` Temperature=300K
R=0.083 L bar `mol^(-1)K^(-1)`
Formula: `pi=(W_(2)RT)/(M_(2)V)`
`pi=(1.71xx0.083xx300)/(342xx0.5)`
answer `pi=0.249` bar.
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