Derive the integrated rate equation for rate constant of a zero reaction.

Explanation

Consider a zero order reaction.
`R to P`
`(-d[R])/(dt) = k[R]^(1)`
Where k is velovity constant of a first order reaction.
`(-d[R])/([R]) = -k.dt`
Inegrating the equation
`int(d[R])/([R]) = -intk.dt`
In `[R] = -kt +1 " "...(1)`
I si constant of integration
WHen t = 0 [R] ` = [R]_(0)` Where `[R]_(0)` is initial concentration of the reaction
In `[R]_(0) = - k xx 0 +1`
`I = "In" [R]_(0)`
Substituing I value in equation (1)
In `[R] = -kt + "In" [R]_(0)`
kt = In `[R]_(0) = "In" [R]`
`k = (2.303)/(t) log""([R]_(0))/([R])`