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Show that t(99%) = 2 xx t(90%)...

Show that `t_(99%) = 2 xx t_(90%)`

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Formula : `k = (2.303)/(t) log""([R]_(0))/([R])`
`(t_(99%))/(t_(90%)) = = ((2.303)/(t)log""(100)/(1))/((2.303)/(k) log""(100)/(10)) rArr (t_(99%))/(t_(90%)) = 2`
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