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Rate constant of a first order reaction ...

Rate constant of a first order reaction is 0.0693 `min^(-1)`. Calculate the percentage of the reactant remaining at the end of 60 minutes.

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Formula : `k = (2.303)/(t) log""([R]_(0))/([R])`
` 0.0693 = (2.303)/(60) log""(100)/([R]) rArr 1.8 = log (100)/([R])`
Antilog `1.8 = (100)/([R])`
`63.1 = (100)/([R]) rArr [R] = 1.584%`
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