Home
Class 12
CHEMISTRY
The boiling point of benzene is 353.23 K...

The boiling point of benzene is 353.23 K when 1.80 g of a non-volatile, non-ionising solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of solute.
`" "`[Given `K_(b)` for benzene = 2.53 K kg `mol^(-1)`]

Promotional Banner

Topper's Solved these Questions

  • ANNUAL EXAMINATION QUESTION PAPER MARCH - 2018

    SUBHASH PUBLICATION|Exercise V. Answer any four of the following . Each question carriers five marks.|17 Videos

  • ANNUAL EXAMINATION QUESTION PAPER MARCH - 2018

    SUBHASH PUBLICATION|Exercise (PART-C) III. Answer any FIVE questions. (Each question carries three marks)|12 Videos

  • ANNUAL EXAM QUESTION PAPER WITH ANSWER MARCH(2016)

    SUBHASH PUBLICATION|Exercise PART E|16 Videos

  • ANNUAL EXAMINATION QUESTION PAPER MARCH 2018

    SUBHASH PUBLICATION|Exercise PART-D|24 Videos

Similar Questions

Explore conceptually related problems

The boiling point of benzene is 353.23 K. When 1.80 g of a non - volatile non - ionisable solute was dissolved in 90 g of benzene, the boiling point raised to 354.11 K.

The boiling point of benzene is 353.23 K . When 1.80 g of a non-volatile solute was dissolved in 90 g benzene, the boiling point is raised to 354.11 K . Calculate the molar mass of the solute. ( K_(b) for benzene is 2.53 K kg mol^(-1) )

(a) The boiling point of benzene is 353.23K. When 1.80g of a non-volatile,non-ionisable solute was dissolved in 90g benzene, the boiling point raised to 354.11K. Calculate molarass of the solute.[Kb for benzene =2.53K kg mol-1]. (b)Define :(i) molality of a solution. (ii) Isotonic solutions.

a) 24 g of a non-volatile, non-electrolyte solute is added to 600 g of water. The boiling point of the resulting solution is 373.35K. Calculate the molar mass of the solute ("Given boiling point of pure water = 373 K and Kb for water=0.52 K kg mol"^(-1)) .

Vapour pressure of benzene is 200 mm of Hg. When 2 gram of a non-volatile solute dissolved in 78 gram benzene, benzene has vapour pressure of 195 mm of Hg. Calculate the molar mass of the solute. [Molar mass of benzene is 78 g/ mol^(-1) ]

A solution containg 12 g of a non-electrolyte substance in 52 g of water gave boiling point elevation of 0.40 K . Calculate the molar mass of the substance. (K_(b) for water = 0.52 K kg mol^(-1))

Aqueous solution of 3% non-volatile solute exerts a pressure of 1 bar at the boiling point of the solvent. Calculate the molar mass of solute.

1.0 g of non - electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.4 K. Find the molar mass of the solute. [Given : Freezing point depression constant of benzene = 5.12 K. kg mol].

A solution containing 12.5 g of non-electrolyte solution in 175g of water gave a boiling point elevation of 0.7 k. calculate the molar mass of the solute if K_(b) for water is 0.52 K kg mol^(-1) .