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A particle having the same charge as of ...

A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of a magnetic field of 0.5 T. If an electric field of 100V/m makes it to move in a straight path, then the mass of the particle is ( Given charge of electron `= 1.6 xx 10^(-19)C`)

A

`9.1 xx 10^(-31) kg`

B

`2.0 xx 10^(-24) kg`

C

`1.6 xx 10^(-27) kg`

D

`1.6 xx 10^(-19) kg`

Text Solution

Verified by Experts

The correct Answer is:
B
`r= (mV)/(qB)" "…….(i)`
and `qE = qVB " "…..(ii)" "implies V = E/B`
From (i) and (ii)
`r = m/q xx ((E//B))/(B) = (mE)/(qB^2) " "implies" "m = (qB^2 r)/E = 2 xx 10^(-24) kg`.
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