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For the reaction, 2A + B to products, wh...

For the reaction, `2A + B to` products, when the concentrations of A and B both were doubled, the rate of the reaction increased from `0.3 mol L^(-1)s^(-1)` to `2.4 mol L^(-1)s^(-1)`. When the concentration of A alone is doubled, the rate increased from `0.3 mol L^(-1)s^(-1)` to `0.6 mol L^(-1)s^(-1)`. What is overall order of reaction ?

Text Solution

Verified by Experts

The correct Answer is:
3
Rate `=k[A]^(m)[B]^(n)`
`"So, "r_(1)=k[A]^(m)[B]^(n)`
`r_(2)=k[2A]^(m)[2B]^(n)`
`r_(3)=k[2A]^(m)[2B]^(n)`
`r_(3)=k[2A]^(m)[B]^(n)`
`(r_(2))/(r_(1))=8=2^(m+n)." So "m+n=3`
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