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0.5 moles of gas A and x moles of gas B ...

0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a container of volume `10 m^(3)` at 1000K. Given R is the gas constant in `jk^(-1)` ,x is :

A

`(4+R)/(2R)`

B

`(2R)/(4-R)`

C

`(2R)/(4+R)`

D

`(4-R)/(2R)`

Text Solution

Verified by Experts

The correct Answer is:
D
`PV=nRT`
`P=200Pa,V=10m^(3),n=0.5+x,T=1000K`
`:.200xx10=(0.5+x)(R)(1000)`
`implies2/R==0.5ximplies(2-0.5R)/R=ximplies(4-R)/(2R)=x`
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