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If a, b and c be three distinct real num...

If a, b and c be three distinct real number in G.P. and `a + b + c = xb`, then x cannot be

A

2

B

4

C

-3

D

-2

Text Solution

Verified by Experts

The correct Answer is:
A
Let common ratio `=r`
Since a,b,c are distinct `r!={0,+-1}`
`xb=b(1+1/r+r)impliesx=r+1/r+1`
If `r gt0,r+1/4gt2{r=1` not allowed}
`r lt 0, r+1/rlt-2{r!=-1}` Hence `xge3` or `xlt-1`
So `x=2` not possible.
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