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If y=y(x) is the solution of the differe...

If `y=y(x)` is the solution of the differential equation `x(dy)/(dx)+2y=x^(2)` satisfying `y(1)=1`, then `y(1/2)` is equal to `(7k)/16`. The value of k is___________________.

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The correct Answer is:
7

`(dy)/(dx)+(2/x)y=x`
I.F.`e^(int 2/x dx)=x^(2)impliesyx^(2)=intx xx x^(2) dximpliesyx^(2)=(x^(4))/4+c`
`y(1)=1impliesc=3/4`
Hence `y=1/(4x^(2))(x^(4)+3)impliesy(1/2)=49/16`
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