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A closed organ pipe has fundamental freq...

A closed organ pipe has fundamental frequency of 1.5 kHz. The number of overtones that can be distinctly heard by a person with this organ pipe will be : (Assume that the highest frequency a person can hear is 20,000 Hz)

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To solve the problem of how many overtones can be distinctly heard from a closed organ pipe with a fundamental frequency of 1.5 kHz, we can follow these steps: ### Step 1: Understand the Harmonics of a Closed Organ Pipe A closed organ pipe produces only odd harmonics. The fundamental frequency (first harmonic) is given as \( f_1 = 1.5 \, \text{kHz} \). The frequencies of the overtones can be expressed as: - First harmonic (fundamental): \( f_1 = \frac{V}{4L} \) - Third harmonic (first overtone): \( f_3 = 3f_1 \) - Fifth harmonic (second overtone): \( f_5 = 5f_1 \) - Seventh harmonic (third overtone): \( f_7 = 7f_1 \) - And so on... ### Step 2: Calculate the Frequencies of the Overtones Using the fundamental frequency: - \( f_1 = 1.5 \, \text{kHz} \) - \( f_3 = 3 \times 1.5 \, \text{kHz} = 4.5 \, \text{kHz} \) - \( f_5 = 5 \times 1.5 \, \text{kHz} = 7.5 \, \text{kHz} \) - \( f_7 = 7 \times 1.5 \, \text{kHz} = 10.5 \, \text{kHz} \) - \( f_9 = 9 \times 1.5 \, \text{kHz} = 13.5 \, \text{kHz} \) - \( f_{11} = 11 \times 1.5 \, \text{kHz} = 16.5 \, \text{kHz} \) - \( f_{13} = 13 \times 1.5 \, \text{kHz} = 19.5 \, \text{kHz} \) ### Step 3: Determine the Maximum Frequency Heard The maximum frequency a person can hear is given as \( 20,000 \, \text{Hz} \) or \( 20 \, \text{kHz} \). ### Step 4: Identify the Highest Overtone Frequency Below 20 kHz From our calculations: - The frequencies of the overtones are: - \( f_1 = 1.5 \, \text{kHz} \) - \( f_3 = 4.5 \, \text{kHz} \) - \( f_5 = 7.5 \, \text{kHz} \) - \( f_7 = 10.5 \, \text{kHz} \) - \( f_9 = 13.5 \, \text{kHz} \) - \( f_{11} = 16.5 \, \text{kHz} \) - \( f_{13} = 19.5 \, \text{kHz} \) The next overtone would be \( f_{15} = 22.5 \, \text{kHz} \), which exceeds the hearing limit of 20 kHz. ### Step 5: Count the Distinct Overtones The overtones that can be distinctly heard are: - First overtone: \( f_3 \) - Second overtone: \( f_5 \) - Third overtone: \( f_7 \) - Fourth overtone: \( f_9 \) - Fifth overtone: \( f_{11} \) - Sixth overtone: \( f_{13} \) Thus, the total number of overtones that can be distinctly heard is 6. ### Final Answer The number of overtones that can be distinctly heard by a person with this organ pipe is **6**. ---

To solve the problem of how many overtones can be distinctly heard from a closed organ pipe with a fundamental frequency of 1.5 kHz, we can follow these steps: ### Step 1: Understand the Harmonics of a Closed Organ Pipe A closed organ pipe produces only odd harmonics. The fundamental frequency (first harmonic) is given as \( f_1 = 1.5 \, \text{kHz} \). The frequencies of the overtones can be expressed as: - First harmonic (fundamental): \( f_1 = \frac{V}{4L} \) - Third harmonic (first overtone): \( f_3 = 3f_1 \) - Fifth harmonic (second overtone): \( f_5 = 5f_1 \) - Seventh harmonic (third overtone): \( f_7 = 7f_1 \) ...
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