Home
Class 12
CHEMISTRY
The ground state energy of hydrogen atom...

The ground state energy of hydrogen atom is -13.6eV . The energy of excited state `He^(+)` ion having principal quantum number n is , -6.04eV . The numerical value of n is ________.

Text Solution

Verified by Experts

The correct Answer is:
3

`E=-13.6xx(z^(2))/(n^(2))eV=-13.6xx((2)^(2))/((3)^(2))=-13.6xx(4)/(9)=-6.04eV`
Promotional Banner

Similar Questions

Explore conceptually related problems

The ground state energy of hydrogen atom is -13.6 eV . The energy of second excited state of He^(+) ion in eV is

The ground state energy of hydrogen atom is -13.6 eV . What is the potential energy of the electron in this state

The ground state energy of hydrogen atom is -13.6eV. What are P.E. and K.E. of electron in this state?

The groud state energy of hydrogen atom is -13.6 eV . When its electron is in first excited state, its exciation energy is

Excitions energy of hydrogen atom is 13.6 eV mathc the following