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A heat source at T = 10^(3) K is connec...

A heat source at T = `10^(3)` K is connected to another heat reservoir at T = `10^(2)` K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 `WK^(-1)m^(-1)`, the energy flux through it in steady state is :

Text Solution

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The correct Answer is:
90
`R=L/(kA)=1/((0.1)A)=10/A`
`I=V/R=(900)/(10/A)=90A`
`I/A=90`
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