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A piece of wood of mass 0.03 kg is dropp...

A piece of wood of mass 0.03 kg is dropped from the top of a building 100 m high. At the same time, a bullet of mass 0.02 kg is fired vertically upward with a velocity of 100 m/s from the ground the bullet gets embedded in the wooded piece after striking. find the height to which the combination rises above the building before it starts falling take `g=10m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
40

`X_("cm")=(0.03xx100)/(0.05)=60cm`
`V_("cm,i")=(0.02xx100)/(0.05)`
`=40` m/s
h above `P=(40^(2))/(2xx10)=1600/20=80`
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