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Hall-Heroult's process is given by :...

Hall-Heroult's process is given by :

A

`2Al_(2)O_(3)+3Cto4Al+3CO_(2)`

B

`Cr_(2)O_(3)+2AltoAl_(2)O_(3)+2Cr`

C

`Cu^(2)+(aq)+H_(2)(g)toCu(s)+2H^(+)(aq)`

D

`ZnO+Coverset("Coke,1673K")toZn+CO`

Text Solution

Verified by Experts

The correct Answer is:
A
In Hall Heroult's process
reaction at cathode : `Al^(3+)+3e^(-)toAl`
reaction at anode : `2O^(2-)toO_(2)+4e^(-)`
As graphite anode is used
`C+O_(2)toCO_(2)`
Hence overall reaction becomes
`Al_(2)O_(3)+CtoAl+CO_(2)`
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