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A process has DeltaH=200Jmol^(-1) and ...

A process has `DeltaH=200Jmol^(-1)` and `DeltaS=40JK^(-1)mol^(-1)`. The minimum temperature above which the process will be spontaneous is ___________K.

Text Solution

Verified by Experts

The correct Answer is:
5
For the process to be spontaneous `DeltaG:-ve`
`DeltaG=DeltaH-Delta(TS)`
At a particular Temperature `DeltaG=DeltaH-TDeltaS`
For spontaneity `DeltaGlt0`
`DeltaH-TDeltaSlt0`
`TDeltaSgtDeltaH`
`T(40)gt200` T=5K `Tgt5`
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