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lf a circle C passing through (4,0) touc...

lf a circle `C` passing through `(4,0)` touches the circle `x^2 + y^2 + 4x-6y-12 = 0` externally at a point `(1, -1),` then the radius of the circle `C` is :-

A

`sqrt(57)`

B

`2sqrt5`

C

5

D

4

Text Solution

Verified by Experts

The correct Answer is:
C

`S=x^(2)+y^(2)+4x-6y-12`
Tangent at (1, -1)
`x-y+2(x+1)-3(y-1)=12`
`3x-4y=7`
Family of such circles , `S+lamdaL=0`
`x^(2)+y^(2)+4x-6y-12+lamda(3x-4y-7)=0`
`16+16-12+lamda(12-7)=0`
`lamda=(-20)/5=-4`
Equation of circle : `x^(2)+y^(2)-8x+10y+16=0`
Radius = 5
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