Home
Class 12
MATHS
The plane passing through the point (4, ...

The plane passing through the point (4, -1, 2) and perallel to the lines `(x+2)/(3)=(y-2)/(-1)=(z+1)/(2)` and `(x-2)/(1)=(y-3)/(2)=(z-4)/(3)` also passes through the point

A

(1, 1, – 1)

B

(–1, – 1, – 1)

C

(–1, – 1, 1)

D

(1, 1, 1)

Text Solution

Verified by Experts

The correct Answer is:
D

Normal vector of plane
`abs({:(hati,hatj,hatk),(3,-1,2),(1,2,3):})`
`=-7hati-7hatj+7hatk`
Let equation of plane be `x+y+z=alpha`
Since it passes through `(4,-1,2)`
`alpha=1`
or `x+y-z=1` Passes through (1, 1, 1)
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the plane passing through (4,-1,2) and parallel to the lines (x+2)/(3)=(y-2)/(-1)=(z+1)/(2) and (x-2)/(1)=(y-3)/(2)=(z-4)/(3)

Find the equation of the line passing through the point (-1,2,3) and perpendicular to the lines (x)/(2)=(y-1)/(-3)=(z+2)/(-2) and (x+3)/(-1)=(y+3)/(2)=(z-1)/(3)

The equation of plane passing through the point (1 ,2 ,3) and parallel to the plane 2x+3y-4z=0 is

Find the equation of the line passing through the point ( 3, 1, 2) and perpendicualr to the lines (x - 1)/(1) = (y - 2) /(2) = ( z - 3) /(3) "and" ( x)/(-3) = (y)/(2) = (z)/(5) .

What is the equation of the line passing through the point (1,2,3) and perpendicular to the lines (x+1)/(1)=(y+2)/(2)=(z+3)/(3) and (x)/(-3)=(y)/(2)=(z)/(5) ?

A plane which passes through the point (3, 2, 1) and the line (x-4)/(1)=(y-7)/(5)=(z-4)/(4) is

cartesian equation of the line which is perpendicular to the lines (x)/(2)=(y)/(1)=(z)/(3) and (x-3)/(-1)=(y-2)/(3)=(z+5)/(5) and passes through the point (1,2,3)