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If the point 3x+4y-24=0 intersects the X...

If the point `3x+4y-24=0` intersects the `X`-axis at the point `A` and the `Y`-axis at the point `B`, then the incentre of the triangle `OAB`, where `O` is the origin, is

A

(4, 4)

B

(3, 4)

C

(2, 2)

D

(4, 3)

Text Solution

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The correct Answer is:
C

`r=(Delta)/S=24/12=2` `therefore` Incentre (2, 2)
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