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The mass and the diameter of a planet a...

The mass and the diameter of a planet are three times the repective value for the Earth. The period of oscillation of a simple pendulum on the Earth is 2 s. The period of oscillation of the same pendulum on the planet would be:

A

`(2)/(sqrt3) s `

B

`3/2 s `

C

`2 sqrt3s `

D

`(sqrt3)/(2) s `

Text Solution

Verified by Experts

The correct Answer is:
C
`(T')/(T)= sqrt((g)/(g '))`
`T'=2 sqrt((GM (3R)^(2))/(R^(2) G(3m)))`
`T' =2 sqrt3s.`
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