The magnitude of torque on a particle of...

The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the orifgin.If the force acting it is 1 N, and the distance of the particle from the origin is 5 m, the angle between the force and the position vector is (in radians):

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The correct Answer is:

6

`tau=FR sin theta`
`sin theta = (2.5)/(1xx5)" "therefore theta =30^(@).`

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