Home
Class 12
CHEMISTRY
The de Broglie wavelenght (lambda) assoc...

The de Broglie wavelenght `(lambda)` associated with a photoelectron varies with the frequency `(v)` of the incident radiation as,[`v_(0)` is threshold frequency]:

A

`lamda = prop(1)/((v-v_(0))^(3/2))`

B

`lamda = prop(1)/((v-v_(0))^(1/4))`

C

`lamda = prop(1)/((v-v_(0))^(1/2))`

D

`lamda prop (1)/((v-v_(0)))`

Text Solution

Verified by Experts

The correct Answer is:
C
`E = hu`
`(hu-hr_(0))=K.E.` (from photoelectric effect)
`lamda = (h)/(sqrt(2mK.E. )), " "lamda prop (h)/(sqrt((u -u _(0))))implies lamda prop (1)/((u-u_(0))^(1//2))`
Promotional Banner

Similar Questions

Explore conceptually related problems

Maximum kinetic energy (E_(k)) of a photoelectron varies with the frequency (v) of the incident radiation as

The De Broglie wavelenght associated with electron in n Bohr orbit is

The kinetic energy (E_(k)) of a photoelectron varies with the frequency (v) of the incident radiation as which of the following graph ?

The maximu kinetic energy (E_(k)) of the photoelectron varies with frequency (v) of the incident light as shown by the curve:

The de-Broglie wavelength lambda associated with charged particle of charge q, mass m and potential difference V is

The de Broglie wavelenght associated with neutrons in thermal equilibrium with matter at 300 K is:

Derive de Broglie wave equation for material particles. (b) Why does photoelectric emission not take place if the frequency of incident radiation is less than threshold frequency ?

When the light of frequency 2 v_(0) (where v_(0) is threshold frequency), is incident on a metal plate, the maximum velocity of electrons emitted is v_(1) . When the frequency of the incident radiation is increased to 5 v_(0) , the maximum velocity of electrons emitted from the same plate is v_(2) . the ratio of v_(1) to v_(2) is