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K(2)HgI(4) is 50% ionised in aqueous sol...

`K_(2)HgI_(4)` is `50%` ionised in aqueous solution. Which of the following are correct ?

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The correct Answer is:
2
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`i=1+ nalpha - alpha " "alpha=` degree of dissociation
`=1 + 3 xx 0.5- 0.5=1.2`
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