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A body is project at t= 0 with a velocit...

A body is project at t= 0 with a velocity `10 ms^-1` at an angle of `60 ^(@)` with the horizontal .The readius of curvature of its trajectory at t=1s is R. Neglecting air resitance and taking acceleration due to gravity `g= 10 ms^-2`, the value of R is :

A

10.3 m

B

2.5m

C

5.1

D

2.8m

Text Solution

Verified by Experts

The correct Answer is:
D
t=1s ,
Vx=5m/s
`Vy=5sqrt3-10xx1`
`V^z/R_c=g cos alpha `
i.e., `R_C=V^2/(g sin alpha) = 26.8/(10 cos alpha)=(26.8sqrt(26.5))/50`
After calculations , we get `R_C` 2.7 m
Closest option is 2.8 m
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