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The force of interaction between two ato...

The force of interaction between two atoms is given by `F= alpha beta exp(-(x^2)/(alphakt))` , where x is the distance ,k is the Boltzmann constant and T is temperature and `alpha " and " beta` are two constans. The dimension of `beta` is :

A

`M^2LT^(-4)`

B

`M^2L^2T^(-2)`

C

`MLT^(-2)`

D

`M^0L^2T^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`L^2/(alpha ((ML^2T^(-2))/theta).theta)=1 rArr alpha =1/(MT)^(-2)`
Also, `MLT^(-2)=alpha beta rArr beta=M^2 LT^(-4)`
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