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In a Wheatstone bridge (see fige ) Res...

In a Wheatstone bridge (see fige ) Resitances P and Q are approximately equal .When `R= 400 Omega` the bridge is blanced .on is inerchanging P and Q ,the value of R, for balance is 405 `Omega ` .The value of X is close to :

A

401.5 ohm

B

402.5 ohm

C

403.5 ohm

D

404.5 ohm

Text Solution

Verified by Experts

The correct Answer is:
B
Let the ratio `P/Q` be `1+delta`
Where `delta` < < 1
So, `400/x = 1+ delta` and `405/x = 1/(1+delta) 1-delta`
Adding `400/x + 405/x =2 `
Solving x= 402.5 `Omega`
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