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A hydrogen atom initially in the ground ...

A hydrogen atom initially in the ground state is excited by absorbing a photon of wavelenght 980 Å.The redius of the atom in the excited state ,in terms of Bohr radius `a_(0)` will be : `(hc= 12500 eV- Å)`

A

`9a_0`

B

`25a^0`

C

`16a^@`

D

`4a^@`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=(hc)/lambda=12500/980 eV approx ` 12.75 eV
This is the energy difference between
n=1 & n=4
Also, `r=r_0 n^2/z`
So, `r/r_0=16`
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