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A solid having density of 9 xx 10^(3) kg...

A solid having density of `9 xx 10^(3) kg m^(-3)` forms face centred cubic crystals of edge length `200 sqrt2` pm. What is the molar mass of the solid ? [Avogadro constant `~= 6 xx 10^(23) mol^(-1), pi ~= 3`]

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The correct Answer is:
A
`9xx10^3 (kg)/m^3=(4xxM)/(6xx10^23 "mole"^(-1))(2sqrt2)^3xx10^(-30)m^3`
`M=(9xx6xx16sqrt2xx10^(-4))/4=305.4xx10^(-4)=0.03054 "km mol"^(-1)`
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