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A particle of mass 20 g is released with...

A particle of mass `20 g` is released with an initial velocity `5m//s` along the curve from the point A, as shown in the figure. The point A is at height h from point B. The particle slides along the frictionless surface. When the particle reaches point B, its angular momentum about O will be : (Take `g=10m//s^2`).

A

`6kg - m^(2)//s`

B

`3kg - m^(2)//s`

C

`8 kg - m^(2)//s`

D

`2kg - m^(2)//s`

Text Solution

Verified by Experts

The correct Answer is:
A
`mgh = (1)/(2) mv_(B)^(2) - (1)/(2)mv_(A)^(2)`
`rarr v_(B) = 15m//s`
`= mv_(B)(OB) = ((20)/(1000)kg)(15 m//s)(20m) = 6kgm^(2)//s`
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