In the circuit shown in figure, when the input voltage of the base resistance is 10 V, `V_(be)` is zero and `V_(ce)` is also zero. Then

Options

A. `25mu A` and 2.8 V
B. `20 mu A` and 2.8 V
C. `25 mu A` and 3.5 V
D. `20 mu A` and 3.5 V

Answer

C

Explanation

`V_(C C) - beta I_(B)R_(C ) = 0`
`I_(B) = (5)/(200 xx 10^(3)) = 2.5 xx 10^(-5)A = 25 mu A , " "V_(B B) - I_(B)R_(B) - 1 = 0`
`V_(B B) = 25 xx 10^(-6) xx 100 xx 10^(3) + 1 = 3.5 V`