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A galavanometer, whose resistance is 50 ...

A galavanometer, whose resistance is 50 ohm has 25 divisions in it. When a current of `4xx10^(-4)` A passes through it,its needle (pointer) deflects by one division. To use this galvanometer as a volmeter of range `2.5V`, it is should be connected to a resistance of :

Text Solution

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The correct Answer is:
200
`i_("full state") = 25 xx 4 xx 10^(-4) = 10^(-2) A`
For voltmeter
`10^(-2) = (2.5)/((50 + R)) R = 200`
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