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The magnetic moment of an octahedral hom...

The magnetic moment of an octahedral homoleptic Mn(II) complex is `5.9BM`. The suitable ligand for this comples is :

A

`NCS^(-)`

B

ethylenediamine

C

`CN^(-)`

D

CO

Text Solution

Verified by Experts

The correct Answer is:
A
mg. Moment `= sqrt(n(n+2)) = sqrt(5(5+2))`
`n = 5 rArr 5` unpaired electrons
This implies weak field ligand i.e, `NCN^(-1)//SCN^(-1)`
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