the metal d-orbitals that are directly facing the ligands in `K_(3)[CO(CN)_(6)[` are :

Options

A. `d_(xz), d_(yz) and d_(z^2)`
B. `d_(xy),d_(xz) and d_(yz)`
C. `d_(x^2-y^2) and d_(z^2)`
D. `d_(xy) and d_(x^2-y^2)`.

Answer

C

Explanation

In `K_(3)[Co(CN)_6]to d^2sp^3` hydridization (Inner orbital complex). So the coordination sphere is octahedral geometry and the ligands are which approaching the central metal atom along the coordinate axes, `d_(x^2-y^2)` and `d_(z^2)` orbitals.