Home
Class 12
PHYSICS
A thermally insulated vessel contains 15...

A thermally insulated vessel contains `150g` of water at `0^(@)C`. Then the air from the vessel is pumped out adiabatically. A fraction of water turms into ice and the rest evaporates at `0^(@)C` itself. The mass of evaporated water will be closest to :
(Latent heat of vaporization of water `=2.10xx10^(6)jkg^(-1)` and Latent heat of Fusion of water `=3.36xx10^(5)jkg^(-1)`)

A

20 g

B

150 g

C

130 g

D

35 g

Text Solution

Verified by Experts

The correct Answer is:
A

Let us assume x grams of water vaporizer
`implies` amount of water frozen `=(150-x)`
Heat gained by vaporized water = Heat lost by frozen water
`implies"x"xxL_V=(150-x)xxL_f`
`"x"xx21xx10^5=(150-x)xx3.36xx10^(5)`
`implies21x=504-3.36ximpliesx=(504)/(24.36)=20.7~~20g`
Promotional Banner

Similar Questions

Explore conceptually related problems

A thermally isolated vessel contains 100g of water at 0^(@)C . When air above the water is pumped out, some of the water freezes and some evaporates at 0^(@)C itself. Calculate the mass of the ice formed such that no water is left in the vessel. Latent heat of vaporization of water at 0^(@)C=2.10xx10^(6)J//kg and latent heat of fusion of ice =3.36xx10^(5)J//kg .

A thermally isolated vessel is maintained inside at 0^@C and contains 200 g of water. When the air above the water is pumped out, some of the water freezes while rest of it evaporated at 0^@C itself. Determine the mass of water that freezed. Take, Latent heat of vapourisation of water at 0^@C = 2.19 xx 10^3 J//g Latent heat of fusion of ice = 3.36 xx 10^2 J//g

A non conducting vessel thermally insulated from its surroundings, contains 100 g of water 0^(@)C . The vessel is connected to a vacuum pump to pump to water vapour. As a result of this, some water is frozen. If the removal of water vapour is continued, what is the maximum amount of water that can be frozen in this manner? Laten heat of vaporisation of water =22.5xx10^(5)Jkg^(-1) and latent heat of fusion of ice =3.36xx10^(5)Jkg^(-1)

A thermally isolated vessel contains 100 g of water at 0^(@)C when air above the water is pumped out, some of the water freezes and some evaporates at 0^(@)C itself. Calculate the mass at 0^(@)C=2.10xx10^(6) j//kg and latent heat of fusion of ice =3.36xx10^(5) j//kg .

At 0^@C a thermally isolated container has 200 g of water. When air above water is pumped out, then some of water evaporates and some of it freezes. What will be the mass of ice formed on freezing when there will be no water left in container? Latent heat of vaporisation of water = 2.2 xx 10^6 J/kg and latent heat of fusion of ice = 3.37 xx 10^5 J/kg.

If 10 g of ice is added to 40 g of water at 15^(@)C , then the temperature of the mixture is (specific heat of water = 4.2 xx 10^(3) j kg^(-1) K^(-1) , Latent heat of fusion of ice = 3.36 xx 10^(5) j kg^(-1) )

A thermal insulated vessel contains some water at 0^(@)C . The vessel is connected to a vaccum pump to pum out water vapour. This results in some water getting frozen. It is given latent heat of vaporization of water at 0^(@)C = 21 xx 10^(5) J//kg and latent heat of freezing of water =3.36 xx 10^(5) J//kg . the maximum percentage amount of water vapour that will be solidified in this manner will be:

A vessel contains a small amount of water at 0^(@)C . If the air in the vessel is rapidly pumped out, it causes freezing of the water. Why? What percentage of the water in the container can be frozen by this method? Latent heat of vaporization and fusion are L_(V) = 540 cal g^(-1) and L_(f) = 80 cal g^(-1) respectively.

A copper calorimeter of mass 190 g contains 300 g of water at 0^(@)C and 50 g of ice at 0^(@)C .Find the amount of steam at 100^(@)C required to raise the temperature of this mixture by 10^(@)C . Given that the specific heat of copperis 420J//kg^(@)C , latent heat of vaporization of water is 2.25xx10^(5)xxJ//kg and latent heat of fusion of ice is 3.36xx10^(5)J//kg .