Given complexes are low spin complexes `[V(CN)_(6)]^(4-)` `[Cr(NH_(3))_(6)]^(2+)` `[Ru(NH_(3))_(6)]^(3+)` `[Fe(CN)_(6)]^(4-)` Then of magnetic `(mu)` for `Fe^(2+),Cr^(+3),Ru^(3+)` is

Options

A. `V^(2)gtRu^(3+)gtCr^(2+)gtFe^(2+)`
B. `Cr^(2+)gtV^(2+)gtRu^(3+)gtFe^(2+)`
C. `V^(2+)gtCr^(2+)gtRu^(3+)gtFe^(2+)`
D. `Cr^(2+)gtRu^(3+)gtFe^(2+)gtV^(2+)`

Answer

C

Explanation

`[V(CN)_6]^(4-),[Fe(CN)_6]^(4-),[Ru(NH_3)_6]^(3+),[Cr(NH_3)_6]^(2+)`
`{:(implies,V^(2+),Fe^(2+),Ru^(3+),Cr^(2+)),(implies,s^@d^3,s^@d^6,s^@d^5,s^@d^4),("No of ",3,0,1,2):}`
Unpaired
electrons (all complex are inner orbital complex because ligands are strong) as, Magnetic moment `mu=sqrt(n+(n+2), n =` no. of unpaired electrons
More the number of unpaired electron more will the value of spin only magnetic moment