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The quantum number of four electrons are...

The quantum number of four electrons are given below:
I. `n=4,l=2,m_l=-2,m_s=-1/2` II. `n=3,l=2,m_l=1,m_s=+1/2`
`III. n = 4 , l =1 ,m _l=0 ,m_s=+1/2`
IV. `n=3,l=1,m_l=1,m_s=-1/2`
The correct order of their increasing energies will be

A

`IgtIIgtIIIgtIV`

B

`IVgtIIIgtIIgtI`

C

`IVgtIIIgtIIgtI`

D

`IgtIIIgtIIgtIV`

Text Solution

Verified by Experts

The correct Answer is:
D
`Eprop(n+)` value
E : Energy of electron in a particular subshell
n : principal quantum number
l : azimuthal quantum number
(I) n + 1 = 6 (II) n+1 = 5 (n=3)
(III) n +1 = 5 (n=4) (IV) n +1 = 4
According to Aufbau’s rule, lower the value of (n + l), lower will be its energy. In case if (n + l) value are same for two different subshell then subshell having lower value of n will have lower energy.
So, correct increasing order of energy is: `(IV) lt (II) lt (III) lt(I)`
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