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If alpha = cos^(-1)((3)/(5)), beta = tan...

If `alpha = cos^(-1)((3)/(5)), beta = tan ^(-1)((1)/(3))` , where `0 lt alpha, beta lt (pi)/(2)`, then `alpha - beta` is equal to

A

`cos^(-1)((9)/(5sqrt(10)))`

B

`sin^(-1)((9)/(5sqrt(10)))`

C

`tan^(-1)((9)/(5sqrt(10)))`

D

`tan^(-1)(9/14)`

Text Solution

Verified by Experts

The correct Answer is:
B

`cosalpha=3/5sinalpha=4/5`
`cosbeta=3/(sqrt(10))sinbeta=1/(sqrt(10))`
`sin(alpha-beta)=sinalphacosbeta-cosalphasinbeta`
`12/(5sqrt(10))-3/(5sqrt(10))=(9)/(5sqrt(10))`
`alpha-beta=sin^(-1)((9)/(5sqrt(10)))`
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