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A block of mass 500g and specific heat 4...

A block of mass `500g` and specific heat `400j.. Kg k` is attached with a spring of spring constant `800 N//m`. Now block is dipped in water of mass `1kg` and specific heat `4184j kg k`. Now the spring is elongated by `2cm` and released. Find rise in temperature of water and block system when block finally comes to rest.

A

`10^(-1) K`

B

`10^(-4) K`

C

`10^(-3) K`

D

`10^(-5) K`

Text Solution

Verified by Experts

The correct Answer is:
D
Potential Energy of spring = Total Head Energy
`(1)/(2) kA^(2) = m_(1)s_(1) Delta theta + m_(2) s_(2) Delta theta`
`Delta theta = ((1)/(2) kA^(2))/(m_(1)s_(1) + m_(2)s_(2)). Delta theta = (400 xx ((2)/(100))^(2))/((4184 + 200)) = 3.6 xx 10^(-5) k`
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